Tan Pi 6
Can anyone solve: tan ((pi / 6) + (3pi / 4))?
Tan (Ã Â € / 6) = 1 / -3.
tan (3Ã Â € / 4) = tan (Ã Â € / 4) = 1 ======> tan (A) = chocolate (€ € € A)
Brown ((leg / 6) + (3pi / 4))
= [tan (Ã € / 6) + tan (3Ã € / 4)] / [1 (tan ((€ / 6)) (tan (3Ã € / 4))] => tan (A + B) = [ Tan (A) + Tan (B)] / [1 Ton (A) Tan (B)
= [1 / -3 1] / [1 (1 / -3) (1)]
= [1 / -3 1] / [1 + 1 / -3]
= [1 / -3 3]
= [1/3 2 / -3 +1] / [1/31]
= [4/3 2/3 (Ã -3)] / [2/3]
= 3 2.
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Tan Pi 6
Tan Pi 6
Can anyone solve: tan ((pi / 6) + (3pi / 4))? 3
Find the correct value without using decimal places.
tan (à € / 6) = 1 / ˆš3
Tan (3Ã Â € / 4) = Tan (Ã Â € / 4) = 1 ======> Tan (A) = Chocolate (Ã € A)
Brown ((leg / 6) + (3pi / 4))
= [Tan (ÃÂ € / 6) + Tan (3Ã € / 4)] / [1 (Tan ((€ / 6)) (Tan (3Ã € / 4))] => Tan (A + B) = [ Tan (A) + Tan (B)] / [1 Ton (A) Tan (B)
= [1/13 1] / [1 (1 / š3) (1)]
= [1 / š3 1] / [1 + 1 / ˆš3]
= [1 / š3 1] [1 / š3 1] / [1 / š3 + 1] [1 / š3 1] ===> Multiply the letters and numbers by [1 / š3 1]
= [1/3 2 / š3 +1] / [1/31]
= [4/3 2/3 (à š3)] / [2/3]
= 3 2
For example, answer your question.
